(x-1)=4x^2+3x-3

Solution for (x-1)=4x^2+3x-3 equation:

(x-1)=4x^2+3x-3

We move all terms to the left:

(x-1)-(4x^2+3x-3)=0

We get rid of parentheses

-4x^2+x-3x-1+3=0

We add all the numbers together, and all the variables

-4x^2-2x+2=0

a = -4; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·(-4)·2
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*-4}=\frac{-4}{-8}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*-4}=\frac{8}{-8}
=-1
$